3x^2+20x-7=11+10(2x+3)

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Solution for 3x^2+20x-7=11+10(2x+3) equation: 


Simplifying
3x2 + 20x + -7 = 11 + 10(2x + 3)

Reorder the terms:
-7 + 20x + 3x2 = 11 + 10(2x + 3)

Reorder the terms:
-7 + 20x + 3x2 = 11 + 10(3 + 2x)
-7 + 20x + 3x2 = 11 + (3 * 10 + 2x * 10)
-7 + 20x + 3x2 = 11 + (30 + 20x)

Combine like terms: 11 + 30 = 41
-7 + 20x + 3x2 = 41 + 20x

Add '-20x' to each side of the equation.
-7 + 20x + -20x + 3x2 = 41 + 20x + -20x

Combine like terms: 20x + -20x = 0
-7 + 0 + 3x2 = 41 + 20x + -20x
-7 + 3x2 = 41 + 20x + -20x

Combine like terms: 20x + -20x = 0
-7 + 3x2 = 41 + 0
-7 + 3x2 = 41

Solving
-7 + 3x2 = 41

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + 3x2 = 41 + 7

Combine like terms: -7 + 7 = 0
0 + 3x2 = 41 + 7
3x2 = 41 + 7

Combine like terms: 41 + 7 = 48
3x2 = 48

Divide each side by '3'.
x2 = 16

Simplifying
x2 = 16

Take the square root of each side:
x = {-4, 4}

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